Pack logtalk -- logtalk-3.86.0/examples/metapredicates/SCRIPT.txt

This file is part of Logtalk https://logtalk.org/ SPDX-FileCopyrightText: 1998-2023 Paulo Moura <pmoura@logtalk.org> SPDX-License-Identifier: Apache-2.0

Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at

http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License.

% start by loading the example and the required library files:

| ?- logtalk_load(metapredicates(loader)). ...

% try the simple meta-predicate definitions from the "goals.lgt" file:

| ?- simple_client::test_whatever.

yes

| ?- simple_client::test_whatever_all.

Hello world! yes

% alternatively:

| ?- simple_client_alt::test_whatever.

yes

| ?- simple_client_alt::test_whatever_all.

Hello world! yes

% note that "user" is a pseudo-object representing the Prolog database; % therefore, the integer comparisons are performed using the standard % Prolog built-in predicates

| ?- sort(user)::sort([3, 1, 4, 2, 9], Sorted).

call: partition([1,4,2,9],3,_358,_359) exit: partition([1,4,2,9],3,[1,2],[4,9]) call: sort([1,2],_740) call: partition([2],1,_967,_968) exit: partition([2],1,[],[2]) call: sort([],_1300) exit: sort([],[]) call: sort([2],_1539) call: partition([],2,_1765,_1766) exit: partition([],2,[],[]) call: sort([],_2093) exit: sort([],[]) call: sort([],_2332) exit: sort([],[]) exit: sort([2],[2]) exit: sort([1,2],[1,2]) call: sort([4,9],_2831) call: partition([9],4,_3058,_3059) exit: partition([9],4,[],[9]) call: sort([],_3391) exit: sort([],[]) call: sort([9],_3630) call: partition([],9,_3856,_3857) exit: partition([],9,[],[]) call: sort([],_4184) exit: sort([],[]) call: sort([],_4423) exit: sort([],[]) exit: sort([9],[9]) exit: sort([4,9],[4,9])

Sorted = [1,2,3,4,9] yes

% test the setof/3 wrapper:

| ?- object::p(L).

L = [1, 2, 3] yes

| ?- object::q(L).

L = [1, 2, 3] yes

% call the meta-predicate apply/2 directly:

| ?- metapreds::test_this.

1, metapreds yes

% send an apply/2 message to self:

| ?- descendant::test_self.

2, descendant yes

% send an apply/2 message from another object:

| ?- test::test_obj.

3, test yes

% use the partition/4 meta-predicate with a predicate defined in the % pseudo-object "user":

| ?- meta::partition(even_integer, [1,2,3,4,5], Included, Excluded).

Included = [2, 4] Excluded = [1, 3, 5] yes

% get a visual illustration of the differences between left and right folds:

| ?- folds::left(Left).

Left = '(((((((((0+1)+2)+3)+4)+5)+6)+7)+8)+9)' yes

| ?- folds::right(Right).

Right = '(1+(2+(3+(4+(5+(6+(7+(8+(9+0)))))))))' yes

% walk a list using left and right folds (note the lambda parameters order):

| ?- meta::fold_left([Y, X, [X|Y]]>>true, [], [1,2,3,4,5,6,7,8,9], R).

R = [9, 8, 7, 6, 5, 4, 3, 2, 1] yes

| ?- meta::fold_right([X, Y, [X|Y]]>>true, [], [1,2,3,4,5,6,7,8,9], R).

R = [1, 2, 3, 4, 5, 6, 7, 8, 9]. yes

% we can compose left folds:

| ?- meta::fold_left([X,Y,Z]>>(Z is X + Y), 0, [1,2,3], Sum).

Sum = 6 yes

| ?- meta::fold_left(meta::fold_left([X,Y,Z]>>(Z is X + Y)), 0, [[1,2,3],[4,5,6]], Sum).

Sum = 21 yes

% use the fold_left/4 meta-predicate with a predicate defined in the % pseudo-object "user":

| ?- meta::fold_left(sum_squares, 0, [1,2,3], Result).

Result = 34 yes

% use the fold_left/4 and fold_right/4 meta-predicates with the atom_concat/3 % Prolog built-in predicate:

| ?- meta::fold_left(atom_concat, 'PREFIX', [abc,def,ghi], Result).

Result = 'PREFIXabcdefghi' yes

| ?- meta::fold_right(atom_concat, 'SUFIX', [abc,def,ghi], Result).

Result = abcdefghiSUFIX yes

% use the fold_left/4 meta-predicate with predicates defined in the object % "predicates":

| ?- meta::fold_left(predicates::sum, 0, [1,2,3,4,5], Result).

Result = 15 yes

| ?- meta::fold_left(predicates::product, 1, [1,2,3,4,5], Result).

Result = 120 yes

| ?- meta::fold_left(predicates::tuple, (0,0), [(1,2), (3,4), (6,4)], Result).

Result = (10, 10) yes

% alternatives to fold_left/4 and fold_right/4 when there isn't an initial value:

| ?- meta::fold_left_1([X,Y,Z]>>(Z is X+Y), [1,2,3,4,5], R). R = 15 yes

| ?- meta::fold_right_1([X,Y,Z]>>(Z is X-Y), [1,2,3,4,5], R). R = 3 yes

| ?- meta::fold_right_1([X,Y,Z]>>(Z is X*Y), [1,2,3,4,5], R). R = 120 yes

% use the scan_left/4 and scan_right/4 meta-predicates with predicates % defined in the object "predicates":

| ?- meta::scan_left(sum_squares, 0, [1,2,3], Result). Result = [0, 1, 5, 34] yes

| ?- meta::scan_right(predicates::sum, 5, [1,2,3,4], Result). Result = [15, 14, 12, 9, 5] yes

% compute a sequence of factorial numbers using a scan of natural numbers % using multiplication:

| ?- meta::scan_left([X,Y,Z]>>(Z is X*Y), 1, [1,2,3,4,5,6], Result). Result = [1, 1, 2, 6, 24, 120, 720] yes

% use the map/2-3 meta-predicates with some Prolog built-in predicates:

| ?- meta::map(integer, [1,2,3,4,5]).

yes

| ?- meta::map(char_code, [a,b,c,d,e], Codes).

Codes = [97, 98, 99, 100, 101] yes

% use the fold_left/4 meta-predicate to calculate Fibonacci numbers:

| ?- fibonacci::nth(10, Fib).

Fib = 55 yes

| ?- fibonacci::nth(Nth, Fib).

Fib = 0 Nth = 0 ? ;

Fib = 1 Nth = 1 ? ;

Fib = 1 Nth = 2 ? ;

Fib = 2 Nth = 3 ? ;

Fib = 3 Nth = 4 ? ;

Fib = 5 Nth = 5 ? ...

% use the map_reduce/5 meta-predicate to give bad news to a company employees:

| ?- company::(company(C1), get_salary(company(C1),S1)).

| ?- company::(company(C1), cut_salary(company(C1), C2), get_salary(C2, S2)).

C1 = [topdept(name('Human Resources'),manager(name('Lisa'),salary(123456)),[]),topdept(name('Development'),manager(name('Anders'),salary(43210)),[subdept(name('Visual Basic'),manager(name('Amanda'),salary(8888)),[]),subdept(name('Visual C#'),manager(name('Erik'),salary(4444)),[])])] C2 = company([topdept(name('Human Resources'),manager(name('Lisa'),salary(61728)),[]),topdept(name('Development'),manager(name('Anders'),salary(21605)),[subdept(name('Visual Basic'),manager(name('Amanda'),salary(4444)),[]),subdept(name('Visual C#'),manager(name('Erik'),salary(2222)),[])])]) S2 = 89999 yes